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(B) Length of the solenoid, $L = 80 \,cm = 0.8 \,m$.Total number of turns, $N = 5 	imes 400 = 2000$.Current, $i = 8 \,A$.Number of turns per unit len

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$2.5 	imes 10^{-2} \,T$

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(B) Length of the solenoid, $L = 80 \,cm = 0.8 \,m$.Total number of turns, $N = 5 	imes 400 = 2000$.Current, $i = 8 \,A$.Number of turns per unit length, $n = \frac{N}{L} = \frac{2000}{0.8} = 2500 \,turns/m$.The magnetic field $B$ inside a long solenoid near its centre is given by $B = \mu_0 ni$.Substituting the values:$B = (4 \pi 	imes 10^{-7} \,T \cdot m/A) 	imes (2500 \,m^{-1}) 	imes (8 \,A)$.$B = 4 	imes 3.14159 	imes 10^{-7} 	imes 20000$.$B = 12.566 	imes 10^{-3} 	imes 2 = 2.513 	imes 10^{-2} \,T$.Thus, the magnitude of the magnetic field is approximately $2.5 	imes 10^{-2} \,T$.

$A$ closely wound solenoid of $80 \,cm$ long has $5$ layers of windings of $400$ turns each. The diameter of the solenoid is $1.8 \,cm$. If the current carried is $8 \,A$, then the magnitude of the magnetic field inside the solenoid near its centre is approximately

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