A straight wire of mass 0.2 ,kg and length 1. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Mass of the wire, $m = 0.2 \,kg$. Length of the wire, $l = 1.5 \,m$. Current, $I = 2 \,A$. Acceleration due to gravity, $g = 10 \,m/s^2$.Th

Vedclass · Accepted Answer

$0.67$

Vedclass · Answer

(B) Given: Mass of the wire, $m = 0.2 \,kg$. Length of the wire, $l = 1.5 \,m$. Current, $I = 2 \,A$. Acceleration due to gravity, $g = 10 \,m/s^2$.The magnetic force $F_m$ acting on a current-carrying wire in a uniform magnetic field is given by $F_m = I l B \sin 	heta$. Since the magnetic field is perpendicular to the wire, $	heta = 90^{\circ}$, so $F_m = I l B$.For the wire to be suspended in mid-air, the upward magnetic force must balance the downward gravitational force (weight) of the wire.$F_m = w$$I l B = m g$Rearranging to solve for $B$:$B = \frac{m g}{I l}$$B = \frac{0.2 	imes 10}{2 	imes 1.5}$$B = \frac{2}{3} \approx 0.67 \,T$Therefore, the magnitude of the magnetic field is $0.67 \,T$.

Similar Questions

$A$ wire carrying current $I$ along the $x$-axis has length $\ell$ and is kept in a magnetic field $\vec{B} = (\hat{i} + 2\hat{j} - 3\hat{k}) B \text{ Wb/m}^2$. The magnitude of the magnetic force acting on the wire is:

Three long straight wires are connected in parallel to each other across a battery of negligible internal resistance. The ratio of their resistances is $3 : 4 : 5$. What is the ratio of the distances of the middle wire from the others if the net force experienced by it is zero?

Two wires $2 \text{ mm}$ apart supply current to a $100 \text{ V}$,$1 \text{ kW}$ heater. The force per metre between the wires is (Given $\mu_0 = 4\pi \times 10^{-7} \text{ T m/A}$)

The magnetic field existing in a region is given by $\vec B = B_0 \left( 5 + \frac{x}{l} \right) \hat k$. $A$ square loop of edge $l$ and carrying a current $i$ is placed with its edges parallel to $x-y$ axes. Find the magnitude of the net magnetic force experienced by the loop.

Vedclass Test Series

Exam Paper Generator

Online Exam Module