$10^{10}$ electrons enter the emitter of a junction transistor in a time of $0.4 \mu s$. If $5 \%$ of the electrons are lost in the base, then the collector current is (in $\text{ mA}$)

The input signal given to a $C.E.$ amplifier having a voltage gain of $126$ is $V_i = 2 \cos \left(12 t + \frac{\pi}{3}\right)$. The corresponding output signal will be

In a common emitter amplifier,the current gain is $62$. The collector resistance and input resistance are $5\,k\Omega$ and $500\,\Omega$ respectively. If the input voltage is $0.01\,V$,the output voltage is $..........\,V$.

$A$ transistor is operated in common emitter configuration at a constant collector voltage $V_C = 1.5 \, V$ such that a change in the base current from $100 \, \mu A$ to $150 \, \mu A$ produces a change in the collector current from $5 \, mA$ to $10 \, mA$. The current gain $\beta$ is:

The graph between the input voltage $(V_{i})$ and the output voltage $(V_{o})$ of a transistor connected in common emitter configuration is shown in the figure. The active, saturation and cutoff regions of the transistor are respectively

When a transistor is used as an amplifier in common emitter configuration,which of the following statements are correct?
$(1)$ The base-emitter junction is forward-biased.
$(2)$ The base-emitter junction is reverse-biased.
$(3)$ The input signal is connected in series with the biasing voltage to the base-emitter junction.
$(4)$ The input signal is connected in series with the biasing voltage to the base-collector junction.