A positive charge Q is situated at the centre | vedclass

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Question

(A) According to Gauss's law, the total electric flux $\phi_{total}$ through any closed surface is given by $\phi_{total} = \frac{Q}{\varepsilon_{0}}$

Vedclass · Accepted Answer

$\frac{Q}{6 \varepsilon_{0}}$

Vedclass · Answer

(A) According to Gauss's law, the total electric flux $\phi_{total}$ through any closed surface is given by $\phi_{total} = \frac{Q}{\varepsilon_{0}}$, where $Q$ is the net charge enclosed by the surface.Since the charge $Q$ is placed at the centre of the cube, the electric flux is symmetrically distributed through all $6$ faces of the cube.Therefore, the electric flux $\phi_{face}$ through any one face of the cube is $\phi_{face} = \frac{\phi_{total}}{6} = \frac{Q}{6 \varepsilon_{0}}$.

$A$ positive charge $Q$ is situated at the centre of a cube. The electric flux through any face of the cube is (in $SI$ units)

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