A liquid of bulk modulus k is compressed by a | vedclass

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(A) The bulk modulus $k$ is defined as $k = -\frac{p}{\Delta V / V}$.Since density $\rho = \frac{m}{V}$, we have $\frac{\Delta \rho}{\rho} = -\frac{\D

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$\frac{k}{10000}$

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(A) The bulk modulus $k$ is defined as $k = -\frac{p}{\Delta V / V}$.Since density $ho = \frac{m}{V}$, we have $\frac{\Delta ho}{ho} = -\frac{\Delta V}{V}$.Given that the density increases by $0.01 \%$, we have $\frac{\Delta ho}{ho} = 0.01 \% = \frac{0.01}{100} = 10^{-4}$.Therefore, $-\frac{\Delta V}{V} = 10^{-4}$.Substituting this into the bulk modulus formula: $p = k 	imes \left( -\frac{\Delta V}{V} ight)$.$p = k 	imes 10^{-4} = \frac{k}{10000}$.

$A$ liquid of bulk modulus $k$ is compressed by applying an external pressure such that its density increases by $0.01 \%$. The pressure applied on the liquid is

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