$A$ line passing through the point of intersection of $x+y=4$ and $x-y=2$ makes an angle $\tan ^{-1}\left(\frac{3}{4}\right)$ with the $x$-axis. It intersects the parabola $y^{2}=4(x-3)$ at points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ respectively. Then, $|x_{1}-x_{2}|$ is equal to

  • A
    $\frac{16}{9}$
  • B
    $\frac{32}{9}$
  • C
    $\frac{40}{9}$
  • D
    $\frac{80}{9}$

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