$\mathop {\lim }\limits_{x \to 0} \frac{{{x^3}}}{{\sin {x^2}}} = $

  • A
    $0$
  • B
    $\frac{1}{3}$
  • C
    $3$
  • D
    $\frac{1}{2}$

Explore More

Similar Questions

$\mathop {\lim }\limits_{x \to 0} \frac{{\cos (\sin x) - 1}}{{{x^2}}} = $

$\lim _{x}$ ${\rightarrow 0} \frac{\tan \left(\left[-\pi^2\right] x^2\right)-x^2 \tan \left(\left[-\pi^2\right]\right)}{\sin ^2 x}$ का मान ज्ञात कीजिए।

$\mathop {\lim }\limits_{x \to 0} \frac{\sin x}{x}$ का मान क्या है?

$\lim _{x \rightarrow 0} \frac{x^2(\tan 2 x-2 \tan x)^2}{(1-\cos 2 x)^4}=$

$\mathop {\lim }\limits_{x \to 0} \frac{{{x^2} - \tan 2x}}{{\tan x}} = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo