$\mathop {\lim }\limits_{x \to \infty } {\left( {1 - \frac{4}{{x - 1}}} \right)^{3x - 1}} = $

  • A
    $e^{12}$
  • B
    $e^{-12}$
  • C
    $e^{4}$
  • D
    $e^{3}$

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$\lim _{x \rightarrow 2}\left(\frac{5 x-8}{8-3 x}\right)^{\frac{3}{2 x-4}} = $

લક્ષની કિંમત શોધો: $\lim_{x \rightarrow 0} \left( \frac{4^x - 1}{2^x - 1} - \frac{\sqrt{4 + 3x} - 2}{x} \right)$

$\lim _{x \rightarrow 3} \frac{x^3-27}{x^2-9} = $

દરેક $t \in \mathbb{R}$ માટે,ધારો કે $[t]$ એ $t$ થી નાનો અથવા તેના જેટલો મહત્તમ પૂર્ણાંક છે. તો $\lim_{x \to 1^+} \frac{(1 - |x| + \sin |1 - x|) \sin (\frac{\pi}{2} [1 - x])}{|1 - x|^2}$ ની કિંમત શોધો.

આપેલ લક્ષની કિંમત શોધો: $\mathop {\lim }\limits_{x \to 3} \frac{x^{4}-81}{2 x^{2}-5 x-3}$

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