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(A) According to Brewster's law, when light is incident at Brewster's angle $\Phi$, the reflected ray and the refracted ray are perpendicular to each

Vedclass · Accepted Answer

$90^\circ$

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(A) According to Brewster's law, when light is incident at Brewster's angle $\Phi$, the reflected ray and the refracted ray are perpendicular to each other.Let $i$ be the angle of incidence, $r$ be the angle of refraction, and $i_p$ be the Brewster's angle $\Phi$.At Brewster's angle, $i = \Phi$.From Snell's law, $\mu = \frac{\sin \Phi}{\sin r}$.Also, Brewster's law states that $\mu = 	an \Phi = \frac{\sin \Phi}{\cos \Phi}$.Comparing the two expressions for $\mu$, we get $\sin r = \cos \Phi = \sin(90^\circ - \Phi)$, which implies $r = 90^\circ - \Phi$.The angle between the reflected ray and the normal is $i = \Phi$.The angle between the refracted ray and the normal is $r = 90^\circ - \Phi$.The angle between the reflected ray and the refracted ray is $180^\circ - (i + r) = 180^\circ - (\Phi + 90^\circ - \Phi) = 180^\circ - 90^\circ = 90^\circ$.

$A$ ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $\Phi$. If $\mu$ denotes the refractive index of glass with respect to air, then what will be the angle between the reflected and refracted rays?

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