int log x , dx = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To evaluate the integral $\int \log x \, dx$,we use the method of integration by parts: $\int u \, dv = uv - \int v \, du$.Let $u = \log x$ and $d

Vedclass · Accepted Answer

$x \log x - x + c$

Vedclass · Answer

(B) To evaluate the integral $\int \log x \, dx$,we use the method of integration by parts: $\int u \, dv = uv - \int v \, du$.Let $u = \log x$ and $dv = dx$.Then,$du = \frac{1}{x} \, dx$ and $v = x$.Applying the formula:$\int \log x \, dx = x \log x - \int x \cdot \frac{1}{x} \, dx + c$$= x \log x - \int 1 \, dx + c$$= x \log x - x + c$.Thus,the correct option is $B$.

$\int \log x \, dx = $

Similar Questions

$\int x^{3} e^{x^{2}} dx =$

Integrate the function: $\left(x^{2}+1\right) \log x$

If $I_n = \int (\log x)^n \, dx$,then $I_n + n I_{n-1} =$

If the primitive of $\cos(\log x)$ is $f(x)\{\cos(g(x)) + \sin(h(x))\}$,then which among the following is true?

$\int \cos 2\theta \log \left( \frac{\cos \theta + \sin \theta }{\cos \theta - \sin \theta } \right) d\theta = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module