$(p \wedge \sim q) \wedge (\sim p \wedge q)$ is

  • A
    $A$ tautology
  • B
    $A$ contradiction
  • C
    Both a tautology and a contradiction
  • D
    Neither a tautology nor a contradiction

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Similar Questions

Consider
Statement-$1$: $(p \wedge \sim q) \wedge (\sim p \wedge q)$ is a fallacy.
Statement-$2$: $(p \rightarrow q) \leftrightarrow (\sim q \rightarrow \sim p)$ is a tautology.

If $\sim p \lor q$ is false, then which of the following is correct?

The logical statement $\sim(p \vee q) \vee(\sim p \wedge q)$ is equivalent to

The negation of the statement "If an integer is greater than $4$ and less than $5$, then it is a multiple of $3$" is:

The statement $(P$ $\Rightarrow Q) \wedge (R$ $\Rightarrow Q)$ is logically equivalent to:

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