Difficult
For the reaction $N_2O_5 \rightarrow 2NO_2 + \frac{1}{2} O_2$,given that:
$-\frac{d[N_2O_5]}{dt} = K_1[N_2O_5]$,
$\frac{d[NO_2]}{dt} = K_2[N_2O_5]$,
$\frac{d[O_2]}{dt} = K_3[N_2O_5]$
What is the relationship between $K_1$,$K_2$,and $K_3$?
$-\frac{d[N_2O_5]}{dt} = K_1[N_2O_5]$,
$\frac{d[NO_2]}{dt} = K_2[N_2O_5]$,
$\frac{d[O_2]}{dt} = K_3[N_2O_5]$
What is the relationship between $K_1$,$K_2$,and $K_3$?
- A$2K_1 = K_2 = 4K_3$
- B$K_1 = K_2 = K_3$
- C$2K_1 = 4K_2 = K_3$
- DNone of these
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For the reaction $2HI \rightleftharpoons H_2 + I_2$,the rate of the reaction is proportional to $[HI]^2$. This means that the reaction is
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The following results have been obtained during the kinetic studies of the reaction:
$2 A + B \rightarrow C + D$
Experiment $[A] / mol \, L^{-1}$ $[B] / mol \, L^{-1}$ Initial rate of formation of $D / mol \, L^{-1} \, min^{-1}$ $I$ $0.1$ $0.1$ $6.0 \times 10^{-3}$ $II$ $0.3$ $0.2$ $7.2 \times 10^{-2}$ $III$ $0.3$ $0.4$ $2.88 \times 10^{-1}$ $IV$ $0.4$ $0.1$ $2.40 \times 10^{-2}$
Determine the rate law and the rate constant for the reaction.
$2 A + B \rightarrow C + D$
| Experiment | $[A] / mol \, L^{-1}$ | $[B] / mol \, L^{-1}$ | Initial rate of formation of $D / mol \, L^{-1} \, min^{-1}$ |
|---|---|---|---|
| $I$ | $0.1$ | $0.1$ | $6.0 \times 10^{-3}$ |
| $II$ | $0.3$ | $0.2$ | $7.2 \times 10^{-2}$ |
| $III$ | $0.3$ | $0.4$ | $2.88 \times 10^{-1}$ |
| $IV$ | $0.4$ | $0.1$ | $2.40 \times 10^{-2}$ |
Determine the rate law and the rate constant for the reaction.
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View SolutionFor a reaction whose rate expression is: Rate $= k[A]^{1/2}[B]^{3/2}$,the order would be
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View SolutionThe following results have been obtained during the kinetic studies of the reaction: $2 \ NO + 2 \ H_2 \longrightarrow N_2 + 2 \ H_2O$
Expt $\frac{-d[NO]}{dt} \ (mol \ L^{-1} \ s^{-1})$ $[NO] \ (mol \ L^{-1})$ $[H_2] \ (mol \ L^{-1})$ $1$ $4.8 \times 10^{-5}$ $1 \times 10^{-2}$ $1 \times 10^{-3}$ $2$ $43.2 \times 10^{-5}$ $3 \times 10^{-2}$ $1 \times 10^{-3}$ $3$ $86.4 \times 10^{-5}$ $3 \times 10^{-2}$ $2 \times 10^{-3}$
| Expt | $\frac{-d[NO]}{dt} \ (mol \ L^{-1} \ s^{-1})$ | $[NO] \ (mol \ L^{-1})$ | $[H_2] \ (mol \ L^{-1})$ |
| $1$ | $4.8 \times 10^{-5}$ | $1 \times 10^{-2}$ | $1 \times 10^{-3}$ |
| $2$ | $43.2 \times 10^{-5}$ | $3 \times 10^{-2}$ | $1 \times 10^{-3}$ |
| $3$ | $86.4 \times 10^{-5}$ | $3 \times 10^{-2}$ | $2 \times 10^{-3}$ |
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