An ideal gas at $27 \, ^\circ C$ is compressed adiabatically such that its volume becomes $8/27$ of its original volume. If $\gamma = 5/3$ for the gas,the increase in temperature of the gas is ..... $K$.

  • A
    $450$
  • B
    $375$
  • C
    $225$
  • D
    $405$

Explore More

Similar Questions

One mole of an ideal gas at an initial temperature of $T$ $K$ does $6R$ of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is $5/3$,the final temperature of the gas will be $(R=8.31 \ J \ mole^{-1} \ K^{-1})$.

During an adiabatic process,the volume of a gas is found to be inversely proportional to the cube of its temperature. The ratio of $\frac{C_p}{C_v}$ for the gas is

Difficult
View Solution

An ideal gas expands adiabatically, $(\gamma = 1.5)$. To reduce the root-mean-square (r.m.s.) velocity of the molecules $4$ times, the gas has to be expanded by a factor of: (in $\times$)

The adiabatic modulus of elasticity of a gas is $2.1 \times 10^5 \ N/m^2$. What will be its isothermal modulus of elasticity? (Given: $\frac{C_p}{C_v} = 1.4$)

An adiabatic process occurs at constant

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo