At 1 atm pressure,which of the following sol | vedclass

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(B) The freezing point depression is given by $\Delta T_f = i 	imes K_f 	imes m$. Since the molality $(m)$ and $K_f$ are constant for all solutions,

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$0.1 \ M \ Sugar$ solution

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(B) The freezing point depression is given by $\Delta T_f = i 	imes K_f 	imes m$. Since the molality $(m)$ and $K_f$ are constant for all solutions,the freezing point depression depends on the van't Hoff factor $(i)$. Lower $i$ value leads to lower freezing point depression,which results in a higher freezing point. For $0.1 \ M \ NaCl$,$i = 2$. For $0.1 \ M \ Sugar$,$i = 1$. For $0.1 \ M \ BaCl_2$,$i = 3$. For $0.1 \ M \ FeCl_3$,$i = 4$. Since $Sugar$ has the lowest van't Hoff factor $(i = 1)$,it will have the minimum freezing point depression and thus the highest freezing point.

At $1 \ atm$ pressure,which of the following solutions will have the highest freezing point?

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