$A$ rotating table completes one revolution in $10 \ s$. Its moment of inertia is $100 \ kg \cdot m^2$. $A$ man of mass $50 \ kg$ stands at the center of the rotating table. If the man moves $2 \ m$ away from the center,what will be the angular velocity of the table in $rad/s$?

  • A
    $\frac{2\pi}{30}$
  • B
    $\frac{20\pi}{30}$
  • C
    $\frac{2\pi}{3}$
  • D
    $2\pi$

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