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(B) The work done in charging a capacitor is stored as potential energy $U$ in the electric field.For a capacitor with capacitance $C$ charged to a po

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$\frac{1}{2}CV^2$

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(B) The work done in charging a capacitor is stored as potential energy $U$ in the electric field.For a capacitor with capacitance $C$ charged to a potential $V$,the energy $U$ is given by the integral of the work done to bring small charge $dq$ to the plates:$U = \int_0^V q \, dV = \int_0^V (CV) \, dV$$U = C \int_0^V V \, dV$$U = C \left[ \frac{V^2}{2} \right]_0^V$$U = \frac{1}{2}CV^2$Therefore,the correct option is $B$.

The energy stored in a capacitor of capacitance $C$ charged to a potential $V$ is:

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