In a semiconductor diode,the forward voltage is increased from $0.5 \ V$ to $0.7 \ V$. As a result,the forward current changes by $1 \ mA$. The forward resistance of the diode is ....... $\Omega$.

The cut-off voltage of the diodes (shown in figure) in forward bias is $0.6 \,V$. The current through the resistor of $40 \,\Omega$ is ........... $mA$.

The curve between charge density and distance near a $P-N$ junction will be:

The circuit shown in the figure contains two ideal diodes $D_1$ and $D_2$. If a cell of emf $3 \text{ V}$ and negligible internal resistance is connected as shown,then the current through the $70 \Omega$ resistance (in ampere) is:

To make a $PN$ junction conducting,

When a forward bias is applied to a $p-n$ junction,what happens to the potential barrier?