In an N-type Ge semiconductor,the mobility of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The conductivity $\sigma$ of an $N$-type semiconductor is given by $\sigma = e n_e \mu_e$,where $e$ is the electronic charge,$n_e$ is the electron

Vedclass · Accepted Answer

$6.25 	imes 10^{15} \ cm^{-3}$

Vedclass · Answer

(A) The conductivity $\sigma$ of an $N$-type semiconductor is given by $\sigma = e n_e \mu_e$,where $e$ is the electronic charge,$n_e$ is the electron concentration,and $\mu_e$ is the electron mobility.Given: $\sigma = 5 \ mho/cm$,$\mu_e = 5000 \ cm^2/V \cdot s$,and $e = 1.6 	imes 10^{-19} \ C$.Rearranging the formula for $n_e$: $n_e = \frac{\sigma}{e \mu_e}$.Substituting the values: $n_e = \frac{5}{1.6 	imes 10^{-19} 	imes 5000}$.$n_e = \frac{5}{8000 	imes 10^{-19}} = \frac{5}{8 	imes 10^{-16}} = 0.625 	imes 10^{16} = 6.25 	imes 10^{15} \ cm^{-3}$.Since it is an $N$-type semiconductor,the concentration of impurity atoms is equal to the electron concentration $n_e$.

In an $N$-type $Ge$ semiconductor,the mobility of electrons is $5000 \ cm^2/V \cdot s$ and the conductivity is $5 \ mho/cm$. If the effect of holes is negligible,what is the concentration of impurity atoms?

Similar Questions

Explain the recombination coefficient of an intrinsic semiconductor and derive the relation $n_i^2 = n_e n_h$.

The process of adding impurities to a pure semiconductor is called

When the conductivity of a semiconductor is only due to the breaking of covalent bonds,the semiconductor is called:

The net charge on an $N-$type semiconductor is

In $P$-type semiconductors,the majority and minority charge carriers are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module