For a prism with a prism angle of $60^\circ$ and a refractive index of $\mu = \sqrt{2}$,the angle of minimum deviation is .......... $^\circ$.

$A$ ray of light is incident at an angle of $60^o$ on one face of a prism of angle $30^o$. The ray emerging out of the prism makes an angle of $30^o$ with the incident ray. The emergent ray is

The angle of a prism is $60^{\circ}$. When light is incident at an angle of $60^{\circ}$ on the prism,the angle of emergence is $40^{\circ}$. The angle of incidence $i$ for which the light ray will deviate the least is such that

$A$ ray of light passes through an equilateral glass prism in such a manner that the angle of incidence is equal to the angle of emergence and each of these angles is equal to $\frac{3}{4}$ of the angle of the prism. The angle of deviation is (in $^{\circ}$)

For a thin prism,if the angle of prism is $4^{\circ}$ and the refractive index is $1.6$,then the angle of minimum deviation will be . . . . . . . (in $^{\circ}$)

In an equilateral prism,the ray undergoes minimum deviation when it is incident at an angle of $50^{\circ}$. The angle of minimum deviation is (in $^{\circ}$)