Light is incident on a glass plate (mu = 1.5) | vedclass

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Question

(A) Given: $\mu = 1.5$,$r = 60^\circ$,$\lambda = 6000 \, \mathring A = 6 	imes 10^{-7} \, m$,$t = 1.2 	imes 10^{-3} \, mm = 1.2 	imes 10^{-6} \, m$

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) Given: $\mu = 1.5$,$r = 60^\circ$,$\lambda = 6000 \, \mathring A = 6 	imes 10^{-7} \, m$,$t = 1.2 	imes 10^{-3} \, mm = 1.2 	imes 10^{-6} \, m$.For a dark band in reflected light,the condition is $2 \mu t \cos r = n \lambda$.Rearranging for $n$: $n = \frac{2 \mu t \cos r}{\lambda}$.Substituting the values: $n = \frac{2 	imes 1.5 	imes 1.2 	imes 10^{-6} 	imes \cos 60^\circ}{6 	imes 10^{-7}}$.Since $\cos 60^\circ = 0.5$: $n = \frac{2 	imes 1.5 	imes 1.2 	imes 10^{-6} 	imes 0.5}{6 	imes 10^{-7}} = \frac{1.8 	imes 10^{-6}}{6 	imes 10^{-7}} = 3$.Thus,the order of the dark band is $3$.

Light is incident on a glass plate $(\mu = 1.5)$ such that the angle of refraction is $60^\circ$. $A$ dark band is observed corresponding to a wavelength of $6000 \, \mathring A$. If the thickness of the glass plate is $1.2 \times 10^{-3} \, mm$,find the order of the interference band.

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