For an odd integer $n \ge 1$,the value of $n^3 - (n-1)^3 + (n-2)^3 - (n-3)^3 + \dots + (-1)^{n-1} 1^3$ is:

  • A
    $\frac{1}{2}(n - 1)^2(2n - 1)$
  • B
    $\frac{1}{4}(n - 1)^2(2n - 1)$
  • C
    $\frac{1}{2}(n + 1)^2(2n - 1)$
  • D
    $\frac{1}{4}(n + 1)^2(2n - 1)$

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Similar Questions

Let $a_1, a_2, a_3, \ldots$ be an arithmetic progression with $a_1=7$ and common difference $8$. Let $T_1, T_2, T_3, \ldots$ be such that $T_1=3$ and $T_{n+1}-T_n=a_n$ for $n \geq 1$. Then,which of the following is/are $TRUE$?
$(A) T_{20}=1604$
$(B) \sum_{k=1}^{20} T_k=10510$
$(C) T_{30}=3454$
$(D) \sum_{k=1}^{30} T_k=35610$

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If the sum of the squares of the first $n$ natural numbers exceeds their sum by $330$,then $n = $

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