If $\alpha$ and $\beta$ are the roots of the equation $x^2 - 2x + 3 = 0$,then find the equation whose roots are $\frac{\alpha - 1}{\alpha + 1}$ and $\frac{\beta - 1}{\beta + 1}$.

  • A
    $3x^2 - 2x - 1 = 0$
  • B
    $3x^2 + 2x + 1 = 0$
  • C
    $3x^2 - 2x + 1 = 0$
  • D
    $x^2 - 3x + 1 = 0$

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