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(C) Let $P(A) = 1/2, P(B) = 1/3$,and $P(C) = 1/4$ be the probabilities of students $A, B$,and $C$ solving the problem respectively.The problem is solv

Vedclass · Accepted Answer

$3/4$

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(C) Let $P(A) = 1/2, P(B) = 1/3$,and $P(C) = 1/4$ be the probabilities of students $A, B$,and $C$ solving the problem respectively.The problem is solved if at least one of them solves it.The probability that the problem is not solved by any of them is given by:$P(	ext{not solved}) = P(A') 	imes P(B') 	imes P(C')$$P(	ext{not solved}) = (1 - 1/2) 	imes (1 - 1/3) 	imes (1 - 1/4)$$P(	ext{not solved}) = (1/2) 	imes (2/3) 	imes (3/4) = 1/4$The probability that the problem is solved is:$P(	ext{solved}) = 1 - P(	ext{not solved})$$P(	ext{solved}) = 1 - 1/4 = 3/4$

$A$ mathematics problem is given to three students $A, B$,and $C$. The probabilities of them solving the problem are $1/2, 1/3$,and $1/4$ respectively. What is the probability that the problem is solved?

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