The probability of a man hitting a target is $3/4$. He tries $5$ times. What is the probability that he hits the target at least $3$ times?

$A$ coin is tossed $4$ times. The probability that at least one head turns up is

$A$ man makes attempts to hit the target. The probability of hitting the target is $\frac{3}{5}$. Then the probability that he hits the target exactly $2$ times in $5$ attempts is:

$A$ variable $X$ takes values $0, 0, 2, 6, 12, 20, ..., n(n-1)$ with frequencies $^nC_0, ^nC_1, ^nC_2, ^nC_3, ^nC_4, ^nC_5, ..., ^nC_n$, respectively. If the mean of this data is $60$, then its median is:

For Binomial distribution $B \left(10, \frac{1}{2} \right)$,if $P(X \leq 2) = m \left( \frac{1}{2} \right)^{10}$,then $m =$ . . . . . . .

Five cards are drawn successively with replacement from a well-shuffled deck of $52$ cards. What is the probability that only $3$ cards are spades?