In the reaction CH_3-CH_2-C equiv CH + HCl to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: Reaction of $1$-butyne with $HCl$. According to Markovnikov's rule,the electrophile $H^+$ adds to the terminal carbon,and the nucleophil

Vedclass · Accepted Answer

$CH_3-CH_2-CCl(I)-CH_3$

Vedclass · Answer

(C) Step $1$: Reaction of $1$-butyne with $HCl$. According to Markovnikov's rule,the electrophile $H^+$ adds to the terminal carbon,and the nucleophile $Cl^-$ adds to the more substituted carbon. The product $B$ is $CH_3-CH_2-CCl=CH_2$ ($2$-chloro$-1-$butene).Step $2$: Reaction of $B$ with $HI$. Again,following Markovnikov's rule,the $H^+$ adds to the $CH_2$ group and the $I^-$ adds to the $CCl$ carbon. The final product $C$ is $CH_3-CH_2-CCl(I)-CH_3$ ($2$-chloro$-2-$iodobutane).

In the reaction $CH_3-CH_2-C \equiv CH + HCl \to B \xrightarrow{HI} C$,what is the product $C$?

Similar Questions

$KMnO_4$ will oxidise acetylene to

What is the product formed when two molecules of $HBr$ are added to $CH_3 - C \equiv CH$?

Which of the following reactions will yield $2,2$-dibromopropane as the product?

When treated with ammoniacal cuprous chloride,which one among the following forms a copper derivative?

$CH_3-C \equiv C-CH_3 \xrightarrow{\text{Cold } KMnO_4} (A)$
Product $(A)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module