What is the product of the Friedel-Crafts rea | vedclass

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Question

(D) The Friedel-Crafts alkylation of benzene with chloroform $(CHCl_3)$ in the presence of anhydrous $AlCl_3$ proceeds through the formation of a carb

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) The Friedel-Crafts alkylation of benzene with chloroform $(CHCl_3)$ in the presence of anhydrous $AlCl_3$ proceeds through the formation of a carbocation intermediate. Initially,benzene reacts with $CHCl_3$ to form benzal chloride $(C_6H_5CHCl_2)$. This intermediate further reacts with more benzene molecules via electrophilic substitution to form triphenylmethane $((C_6H_5)_3CH)$. Since the reaction continues until all chlorine atoms are replaced by phenyl groups,the final major product is triphenylmethane,but the reaction mixture contains intermediate products like $(C_6H_5)_2CHCl$ and $C_6H_5CHCl_2$ depending on the stoichiometry. Thus,all the given options represent products formed during the reaction sequence.

List-$I$	List-$II$
$A$. Finkelstein reaction	$I$. $SbF_3$
$B$. Swarts reaction	$II$. $Na$, dry ether
$C$. Sandmeyer's reaction	$III$. $NaI$
$D$. Fittig reaction	$IV$. $Cu_2Cl_2$

What is the product of the Friedel-Crafts reaction of benzene with chloroform?

Similar Questions

Match the List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. Finkelstein reaction $I$. $SbF_3$
$B$. Swarts reaction $II$. $Na$, dry ether
$C$. Sandmeyer's reaction $III$. $NaI$
$D$. Fittig reaction $IV$. $Cu_2Cl_2$

Choose the correct answer from the options given below:

Which of the following undergoes hydrolysis most easily?

Product $A$ is

Assertion : Alkylbenzene is not prepared by Friedel-Crafts alkylation of benzene.
Reason : Alkyl halides are less reactive than acyl halides.

Select the correct statement:

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