Select the correct statement:
- APure chloroform gives a precipitate with $aq. AgNO_3$.
- BChloroform is used as an analgesic.
- CIodoform is an anesthetic.
- D$Ph-CO-CH_2-CO-Ph$ with $NaOH + I_2$ gives a yellow precipitate.
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Similar Questions
The reaction of toluene with $Cl_2$ in the presence of $FeCl_3$ gives $X$ and the reaction in the presence of light gives $Y.$ Thus,$X$ and $Y$ are
MediumAIPMT 2010
View SolutionMatch List-$I$ with List-$II$:
List-$I$ (Reaction) List-$II$ (Name of reaction) $A$. $2C_6H_5X + 2Na \xrightarrow{\text{Dry Ether}} C_6H_5-C_6H_5 + 2NaX$ $I$. Lucas reaction $B$. $ArN_2^{+} X^{-} \xrightarrow[HCl]{Cu} ArCl + N_2 \uparrow + CuX$ $II$. Finkelstein reaction $C$. $C_2H_5Br + NaI \xrightarrow{\text{Acetone}} C_2H_5I + NaBr$ $III$. Fittig reaction $D$. $(CH_3)_3COH \xrightarrow[ZnCl_2]{HCl} (CH_3)_3CCl + H_2O$ $IV$. Gatterman reaction
Choose the correct answer from the options given below:
| List-$I$ (Reaction) | List-$II$ (Name of reaction) |
|---|---|
| $A$. $2C_6H_5X + 2Na \xrightarrow{\text{Dry Ether}} C_6H_5-C_6H_5 + 2NaX$ | $I$. Lucas reaction |
| $B$. $ArN_2^{+} X^{-} \xrightarrow[HCl]{Cu} ArCl + N_2 \uparrow + CuX$ | $II$. Finkelstein reaction |
| $C$. $C_2H_5Br + NaI \xrightarrow{\text{Acetone}} C_2H_5I + NaBr$ | $III$. Fittig reaction |
| $D$. $(CH_3)_3COH \xrightarrow[ZnCl_2]{HCl} (CH_3)_3CCl + H_2O$ | $IV$. Gatterman reaction |
Choose the correct answer from the options given below:
Assertion : Alkylbenzene is not prepared by Friedel-Crafts alkylation of benzene.
Reason : Alkyl halides are less reactive than acyl halides.
Reason : Alkyl halides are less reactive than acyl halides.
Match the following lists:
List-$I$ List-$II$ $(A)$ Benzene $1$. Phosgene $(B)$ Ethylene $2$. Silver mirror $(C)$ Acetaldehyde $3$. Mustard gas $(D)$ Chloroform $4$. $(4n + 2) \pi$ electrons $5$. Carbylamine
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ Benzene | $1$. Phosgene |
| $(B)$ Ethylene | $2$. Silver mirror |
| $(C)$ Acetaldehyde | $3$. Mustard gas |
| $(D)$ Chloroform | $4$. $(4n + 2) \pi$ electrons |
| $5$. Carbylamine |
$C_3H_7I$ $(P)$ $\xrightarrow[\text{alc. } KOH]{\Delta}$ $Q$ $\xrightarrow{NBS}$ $R$ $\xrightarrow{KCN}$ $CH_2 = CH - CH_2 - CN$. $P$ can be:
Medium
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