Which of the following is the most stable carbanion?

  • A
    $p-Cl-C_6H_4-CH_2^-$
  • B
    $p-NO_2-C_6H_4-CH_2^-$
  • C
    $p-OCH_3-C_6H_4-CH_2^-$
  • D
    $C_6H_5-CH_2^-$

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Similar Questions

Rank the transition states that occur during the following reaction steps in order of increasing stability (least $\to$ most stable):
$1.$ $CH_3-O^+H_2 \to CH_3^+ + H_2O$
$2.$ $(CH_3)_3C-O^+H_2 \to (CH_3)_3C^+ + H_2O$
$3.$ $(CH_3)_2CH-O^+H_2 \to (CH_3)_2CH^+ + H_2O$

The total number of electrons around the carbon atom of a methyl free radical is:

Based upon an understanding of product stability,predict the product formed when the following dianion reacts with one equivalent of acid $(H^+)$.

The major products $A$ and $B$ in the following reactions are:

State True or False for the following statements:
$(i)$ Only carbocation is formed by homolytic cleavage of a bond.
$(ii)$ By heterolytic cleavage of a bond,a carbocation or carbanion is formed.
$(iii)$ The carbon of a carbanion is $sp^2$ and the carbon of a carbocation is $sp^3$.
$(iv)$ The carbon of a carbanion is $sp^3$ and the carbon of a carbocation is $sp^2$.

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