What is the decreasing order of basic strengt | vedclass

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Question

(A) The basic strength of a species is inversely proportional to the stability of its conjugate acid. $1$. The conjugate acids are: $H_2O, NH_3, HC \e

Vedclass · Accepted Answer

$CH_3 - \mathop C\limits^\Theta H_2 > \mathop N\limits^\Theta H_2 > HC \equiv \mathop C\limits^\Theta > \mathop O\limits^\Theta H$

Vedclass · Answer

(A) The basic strength of a species is inversely proportional to the stability of its conjugate acid. $1$. The conjugate acids are: $H_2O, NH_3, HC \equiv CH, CH_3-CH_3$. $2$. The acidity order of these conjugate acids is: $H_2O > NH_3 > HC \equiv CH > CH_3-CH_3$ (based on electronegativity of the atom bearing the negative charge: $O > N > sp-C > sp^3-C$). $3$. Therefore,the basic strength order is the reverse: $CH_3 - \mathop C\limits^\Theta H_2 > HC \equiv \mathop C\limits^\Theta > \mathop N\limits^\Theta H_2 > \mathop O\limits^\Theta H$. Note: The provided options do not contain the correct order derived. However,based on standard chemical principles,the correct order is $CH_3 - \mathop C\limits^\Theta H_2 > HC \equiv \mathop C\limits^\Theta > \mathop N\limits^\Theta H_2 > \mathop O\limits^\Theta H$. Since this is not listed,we select the option that best represents the trend of increasing basicity with decreasing electronegativity.

What is the decreasing order of basic strength for the following species: $\mathop O\limits^\Theta H, \mathop N\limits^\Theta H_2, HC \equiv \mathop C\limits^\Theta, CH_3 - \mathop C\limits^\Theta H_2$?

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