When (n-1)d orbitals participate in the hybri | vedclass

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Question

(B) In coordination chemistry,when $(n-1)d$ orbitals are used for hybridization (e.g.,$d^2sp^3$ hybridization),the complex is referred to as an inner

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Low spin complex

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(B) In coordination chemistry,when $(n-1)d$ orbitals are used for hybridization (e.g.,$d^2sp^3$ hybridization),the complex is referred to as an inner orbital complex.These complexes are typically formed by strong field ligands that cause pairing of electrons in the $(n-1)d$ orbitals.Due to this pairing,the number of unpaired electrons decreases,resulting in a lower magnetic moment and a lower total spin value.Therefore,these are known as low spin complexes.

When $(n-1)d$ orbitals participate in the hybridization of a coordination complex,the resulting complex is known as:

Similar Questions

Select the incorrect match.

Explain the complex species $[Ni(CN)_4]^{2-}$ on the basis of Valence Bond Theory $(VBT)$.

Identify the number of unpaired electrons present and the geometry,respectively,of the complex $[CoF_6]^{3-}$ (given atomic number of $Co = 27$).

Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

$[NiCl_{4}]^{2-}$ is paramagnetic while $[Ni(CO)_{4}]$ is diamagnetic though both are tetrahedral. Why?

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