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(B) The complex $[Co(NH_3)_3(NO_3)_3]$ is of the type $[MA_3B_3]$.For octahedral complexes of the type $[MA_3B_3]$,there are two geometric isomers pos

Vedclass · Accepted Answer

$2$

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(B) The complex $[Co(NH_3)_3(NO_3)_3]$ is of the type $[MA_3B_3]$.For octahedral complexes of the type $[MA_3B_3]$,there are two geometric isomers possible:$1$. Facial $(fac)$ isomer: In this isomer,the three identical ligands occupy the corners of one triangular face of the octahedron.$2$. Meridional $(mer)$ isomer: In this isomer,the three identical ligands occupy the meridian of the octahedron.Therefore,the total number of geometric isomers is $2$.

What is the number of geometric isomers for $[Co(NH_3)_3(NO_3)_3]$?

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