The complex ion [Pt(NO_2)(py)(NH_3)(NH_2OH)]^ | vedclass

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(C) The complex $[Pt(NO_2)(py)(NH_3)(NH_2OH)]^{+}$ is a square planar complex of the type $[M(abcd)]^n+$. In a square planar complex with four differe

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$3$

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(C) The complex $[Pt(NO_2)(py)(NH_3)(NH_2OH)]^{+}$ is a square planar complex of the type $[M(abcd)]^n+$. In a square planar complex with four different ligands,the number of geometric isomers is given by $3$. Let the ligands be $a, b, c, d$. We can fix one ligand (say $a$) and arrange the others in different positions relative to it. $1$. $a$ trans to $b$ (with $c$ trans to $d$) $2$. $a$ trans to $c$ (with $b$ trans to $d$) $3$. $a$ trans to $d$ (with $b$ trans to $c$) Thus,there are $3$ possible geometric isomers.

List-$I$ (Complex ion)	List-$II$ (Calculated spin only magnetic moment $(BM)$)
$A$. $[Cr(H_2O)_6]^{2+}$	$I$. $3.87$
$B$. $[Co(H_2O)_6]^{2+}$	$II$. $5.92$
$C$. $[Cu(H_2O)_6]^{2+}$	$III$. $4.90$
$D$. $[Mn(H_2O)_6]^{2+}$	$IV$. $1.73$

The complex ion $[Pt(NO_2)(py)(NH_3)(NH_2OH)]^{+}$ exhibits how many geometric isomers?

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