Find the coordinates of the point where the line $3x - 2y - 6 = 0$ intersects the $Y$-axis.

If $(0, 0)$,$(-2, 1)$,and $(5, 2)$ are the vertices of a triangle,then the equation of the line passing through the centroid and parallel to the line $x - 2y = 6$ is:

Find the equation of a straight line which passes through the point $(-1, -1)$ and makes an angle $150^{\circ}$ with the positive direction of the $X$-axis.

Find the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point $(2,3)$.

If $a, b$ are positive real numbers such that the lines $ax + 9y = 5$ and $4x + by = 3$ are parallel,then the least possible value of $a + b$ is

Reduce the equation $y-2=0$ into the normal form $x \cos \omega + y \sin \omega = p$. Find the perpendicular distance from the origin $(p)$ and the angle between the perpendicular and the positive $x$-axis $(\omega)$.