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(C) The equation of the circle is $2x^2 + 2y^2 = 3$.Dividing by $2$,we get $x^2 + y^2 = \frac{3}{2}$,or $x^2 + y^2 - \frac{3}{2} = 0$.The length of th

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$\frac{7\sqrt{2}}{2}$

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(C) The equation of the circle is $2x^2 + 2y^2 = 3$.Dividing by $2$,we get $x^2 + y^2 = \frac{3}{2}$,or $x^2 + y^2 - \frac{3}{2} = 0$.The length of the tangent from a point $(x_1, y_1)$ to a circle $x^2 + y^2 + 2gx + 2fy + c = 0$ is given by $\sqrt{x_1^2 + y_1^2 + 2gx_1 + 2fy_1 + c}$.Substituting $(1, 5)$ into the equation $x^2 + y^2 - \frac{3}{2} = 0$:Length $= \sqrt{1^2 + 5^2 - \frac{3}{2}} = \sqrt{1 + 25 - 1.5} = \sqrt{26 - 1.5} = \sqrt{24.5}$.$\sqrt{24.5} = \sqrt{\frac{49}{2}} = \frac{7}{\sqrt{2}} = \frac{7\sqrt{2}}{2}$.

The length of the tangent drawn from the point $(1, 5)$ to the circle $2x^2 + 2y^2 = 3$ is ...

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