In which quadrant does the vertex of the para | vedclass

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(D) The given equation of the parabola is $y^2 + 2y + x = 0$. Completing the square for $y$,we get $(y^2 + 2y + 1) - 1 + x = 0$. This simplifies to $(

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(D) The given equation of the parabola is $y^2 + 2y + x = 0$. Completing the square for $y$,we get $(y^2 + 2y + 1) - 1 + x = 0$. This simplifies to $(y + 1)^2 = -(x - 1)$. Comparing this with the standard form $(y - k)^2 = -4a(x - h)$,the vertex $(h, k)$ is $(1, -1)$. Since the $x$-coordinate is positive and the $y$-coordinate is negative,the vertex $(1, -1)$ lies in the $IV$ quadrant.

In which quadrant does the vertex of the parabola $y^2 + 2y + x = 0$ lie?

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