The equation of the family of circles having the same radical axis as the circles $x^2 + y^2 = 4$ and $x^2 + y^2 + 2x + 4y = 6$ is:
- A$x^2 + y^2 + \lambda x + 2\lambda y - (4 + \lambda) = 0$
- B$x^2 + y^2 + \lambda(x - 2y - 1) = 0$
- C$x^2 + y^2 + \lambda(x + 2y - 4) = 1$
- D$x^2 + y^2 + 2\lambda x + \lambda y - (4 + \lambda) = 0$
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View SolutionIn List-$I$,a pair of circles is given in $A$,$B$,$C$ and in List-$II$,the angle between those pairs of circles is given. Match the items from List-$I$ to List-$II$.
List-$I$ List-$II$ $(A)$ $(x-2)^2+y^2=2$,$(x-2)^2+(y-1)^2=1$ $I.$ $90^{\circ}$ $(B)$ $x^2+y^2-6x-6y+9=0$,$x^2+y^2-4x+4y-9=0$ $II.$ $135^{\circ}$ $(C)$ $x^2+y^2+4x-14y+28=0$,$x^2+y^2+4x-5=0$ $III.$ $60^{\circ}$ $IV.$ $30^{\circ}$
The correct matching is
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ $(x-2)^2+y^2=2$,$(x-2)^2+(y-1)^2=1$ | $I.$ $90^{\circ}$ |
| $(B)$ $x^2+y^2-6x-6y+9=0$,$x^2+y^2-4x+4y-9=0$ | $II.$ $135^{\circ}$ |
| $(C)$ $x^2+y^2+4x-14y+28=0$,$x^2+y^2+4x-5=0$ | $III.$ $60^{\circ}$ |
| $IV.$ $30^{\circ}$ |
The correct matching is
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