If the lines $3x - 4y - 7 = 0$ and $2x - 3y - 5 = 0$ are two diameters of a circle with an area of $49\pi$ square units,then the equation of the circle is:

  • A
    $x^2 + y^2 + 2x - 2y - 62 = 0$
  • B
    $x^2 + y^2 - 2x + 2y - 62 = 0$
  • C
    $x^2 + y^2 - 2x + 2y - 47 = 0$
  • D
    $x^2 + y^2 + 2x - 2y - 47 = 0$

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