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(B) Let the equation of the ellipse be $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ where $a > b$.The distance between the foci is $2ae = 2h$,so $ae = h$.T

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$\frac{x^2}{k^2} + \frac{y^2}{k^2 - h^2} = 1$

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(B) Let the equation of the ellipse be $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ where $a > b$.The distance between the foci is $2ae = 2h$,so $ae = h$.The endpoints of the minor axis are $(0, b)$ and $(0, -b)$.The focal distance of an endpoint of the minor axis is the distance from $(0, b)$ to a focus $(ae, 0)$,which is $\sqrt{(ae - 0)^2 + (0 - b)^2} = \sqrt{a^2e^2 + b^2}$.Given this distance is $k$,we have $\sqrt{a^2e^2 + b^2} = k$,so $a^2e^2 + b^2 = k^2$.Substituting $ae = h$,we get $h^2 + b^2 = k^2$,which implies $b^2 = k^2 - h^2$.We also know $b^2 = a^2(1 - e^2) = a^2 - a^2e^2 = a^2 - h^2$.Thus,$a^2 - h^2 = k^2 - h^2$,which gives $a^2 = k^2$.Substituting $a^2 = k^2$ and $b^2 = k^2 - h^2$ into the standard equation,we get $\frac{x^2}{k^2} + \frac{y^2}{k^2 - h^2} = 1$.

If the focal distance of an endpoint of the minor axis of an ellipse (taking its axes as the $x$ and $y$ axes respectively) is $k$ and the distance between its foci is $2h$,then its equation is:

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