If P is any point on the ellipse frac{x^{2}}{ | vedclass

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(D) The given equation of the ellipse is $\frac{x^{2}}{36}+\frac{y^{2}}{16}=1$. Comparing this with the standard form $\frac{x^{2}}{a^{2}}+\frac{y^{2}

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$12$

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(D) The given equation of the ellipse is $\frac{x^{2}}{36}+\frac{y^{2}}{16}=1$. Comparing this with the standard form $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$,we get $a^{2}=36$,which implies $a=6$. By the definition of an ellipse,the sum of the focal distances of any point $P$ on the ellipse is equal to the length of the major axis. Therefore,$PS + PS^{\prime} = 2a$. Substituting the value of $a$,we get $PS + PS^{\prime} = 2 	imes 6 = 12$.

If $P$ is any point on the ellipse $\frac{x^{2}}{36}+\frac{y^{2}}{16}=1$ and $S$ and $S^{\prime}$ are the foci,then $PS + PS^{\prime}$ is equal to

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