The circle x^2 + y^2 + 6y = 0 touches which o | vedclass

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(B) The given equation of the circle is $x^2 + y^2 + 6y = 0$.Completing the square for the $y$-terms:$x^2 + (y^2 + 6y + 9) = 9$$x^2 + (y + 3)^2 = 3^2$

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$x$-axis at the origin

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(B) The given equation of the circle is $x^2 + y^2 + 6y = 0$.Completing the square for the $y$-terms:$x^2 + (y^2 + 6y + 9) = 9$$x^2 + (y + 3)^2 = 3^2$Comparing this with the standard form $(x - h)^2 + (y - k)^2 = r^2$,the center is $(0, -3)$ and the radius $r = 3$.Since the distance from the center $(0, -3)$ to the $x$-axis is $|-3| = 3$,which is equal to the radius,the circle touches the $x$-axis.Since the $x$-coordinate of the center is $0$,the circle touches the $x$-axis at the origin $(0, 0)$.

The circle $x^2 + y^2 + 6y = 0$ touches which of the following?

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