$A$ body is projected horizontally with a velocity of $\sqrt{2gh}$ from the top of a tower of height $h$. It hits the ground at a distance $x$ from the tower. Then $x =$

  • A
    $h$
  • B
    $\frac{h}{2}$
  • C
    $2h$
  • D
    $\frac{2h}{3}$

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