For a simple harmonic motion given by $x = 0.01 \sin 100\pi (t + 0.05)$,what is the time period in $\text{sec}$?

If a $SHM$ is represented by $\frac{d^2x}{dt^2} + ax = 0$,its time period is:

The equation of $SHM$ of a particle is given as $2 \frac{d^2x}{dt^2} + 32x = 0$,where $x$ is the displacement from the mean position of rest. The period of its oscillation (in seconds) is

If the displacement of a particle is given by $x = 3 \sin (5\pi t) + 4 \cos (5\pi t) \text{ cm}$,what is the amplitude of the particle?

Define simple harmonic motion and explain it.

$A$ particle of mass $m$ is under the influence of a force $F$ which varies with the displacement $x$ according to the relation $F = -kx + F_0$,where $k$ and $F_0$ are constants. The particle,when disturbed,will oscillate: