If a $SHM$ is represented by $\frac{d^2x}{dt^2} + ax = 0$,its time period is:

If the displacement of a particle executing simple harmonic motion is given by $x = 0.5 \cos (125.6 t)$,then the time period of oscillation of the particle is nearly. (Here $x$ is displacement in metre and $t$ is time in second) (in $s$)

The equation of motion of a particle is $x = a \cos(\alpha t)$. The motion is

The figure shows the circular motion of a particle. The radius of the circle is $B$. The particle starts at $t=0$ from the positive $y$-axis and moves clockwise. The simple harmonic motion of the $x$-projection of the radius vector of the rotating particle is given by:

Generation and propagation of sound and electromagnetic waves can be understood by which motion?

The motion of a particle as per $x = A \sin \omega t + B \cos \omega t$ is :-