A coin is placed at the bottom of a glass sla | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The apparent depth $d'$ of an object seen through multiple slabs is given by $d' = \sum \frac{x_i}{\mu_i}$.Here,the total apparent depth of the co

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(C) The apparent depth $d'$ of an object seen through multiple slabs is given by $d' = \sum \frac{x_i}{\mu_i}$.Here,the total apparent depth of the coin as seen from the top is the sum of the apparent depths through each slab.The coin is at the bottom of the slab with refractive index $\mu_1 = 3$ and thickness $x$.The slab with refractive index $\mu_2 = \mu$ and thickness $x$ is placed on top.The apparent depth of the coin is $d' = \frac{x}{\mu_1} + \frac{x}{\mu_2}$.Given that the coin appears to be at the interface of the two slabs,the apparent depth $d'$ must be equal to the thickness of the top slab,which is $x$.Therefore,$x = \frac{x}{3} + \frac{x}{\mu}$.Dividing both sides by $x$,we get $1 = \frac{1}{3} + \frac{1}{\mu}$.$\frac{1}{\mu} = 1 - \frac{1}{3} = \frac{2}{3}$.$\mu = \frac{3}{2} = 1.5$.

$A$ coin is placed at the bottom of a glass slab of refractive index $3$ and thickness $x$. Another glass slab of refractive index $\mu$ and thickness $x$ is placed on top of it. If the coin appears to be at the interface of the two slabs,then $\mu = $ . . . . . .

Similar Questions

$A$ coin is placed at the bottom of an empty beaker and is focused by a microscope. When water is poured into the beaker to a height of $10 \, cm$,how much must the microscope be moved to focus it again?

Three immiscible liquids of densities $d_1 > d_2 > d_3$ and refractive indices $\mu_1 > \mu_2 > \mu_3$ are put in a beaker. The height of each liquid column is $\frac{h}{3}$. $A$ dot is made at the bottom of the beaker. For near normal vision,find the apparent depth of the dot.

$A$ paraxial beam is incident on a glass $(n = 1.5)$ hemisphere of radius $R = 6\, cm$ in air as shown. The distance of the point of convergence $F$ from the plane surface of the hemisphere is......$cm$.

An air bubble in a glass slab $(\mu = 1.5)$ appears to be $5 \, cm$ deep when viewed through one face and $2 \, cm$ deep when viewed through the opposite face. What is the thickness of the slab in $cm$?

$A$ monochromatic ray of light travels through a glass slab and a water column. The number of waves in a glass slab of thickness $4 \ cm$ is the same as in a water column of height $5 \ cm$. If the refractive index of glass is $\frac{5}{3}$,then the refractive index of water is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module