Which of the following is the correct order o | vedclass

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(C) The acidic strength depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $RCOOH$ (Carboxylic acid) is the

Vedclass · Accepted Answer

$RCOOH > HOH > ROH > HC \equiv CH$

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(C) The acidic strength depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $RCOOH$ (Carboxylic acid) is the strongest acid due to the resonance stabilization of the carboxylate ion $(RCOO^-)$.$2$. $HOH$ $(H_2O)$ is more acidic than $ROH$ (Alcohols) because the alkyl group $(R-)$ in $ROH$ is electron-donating ($+I$ effect),which destabilizes the alkoxide ion $(RO^-)$.$3$. $HC \equiv CH$ (Terminal alkyne) is the weakest acid among these because the negative charge on the $sp$ hybridized carbon is less stable than the negative charge on the oxygen atom.Therefore,the correct order is: $RCOOH > HOH > ROH > HC \equiv CH$.

Which of the following is the correct order of acidic strength?

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