(A) $LiAlH_4$ is a strong reducing agent that reduces esters to primary alcohols. The reaction is as follows:$R-COOR' + 4[H] \xrightarrow{LiAlH_4} R-C

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Two units of alcohol are obtained.

(A) $LiAlH_4$ is a strong reducing agent that reduces esters to primary alcohols. The reaction is as follows:$R-COOR' + 4[H] \xrightarrow{LiAlH_4} R-CH_2OH + R'OH$In this reaction,the ester is cleaved to produce two alcohol molecules: one derived from the acyl part $(R-CH_2OH)$ and one from the alkoxy part $(R'OH)$.

Class 12 Chemistry 8-2.Carboxylic acids and Their derivative Properties of Carboxylic Acids and Their Derivatives

Medium

What happens when $LiAlH_4$ is added to an ester?

A
Two units of alcohol are obtained.
B
One unit of alcohol and one unit of acid are obtained.
C
Two units of acid are obtained.
D
None of these.

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8-2.Carboxylic acids and Their derivative

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Properties of Carboxylic Acids and Their Derivatives

What is formed when ethyl alcohol reacts with acetyl chloride?

Medium

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What is the correct order of acidity for the given compounds?

Easy

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The acidity of alcohol,phenol,and carboxylic acid differs. Demonstrate their reactivity with $Na$,$NaOH$,and $NaHCO_3$ using the table below.

Compound Reaction with $Na$ metal Reaction with $NaOH$ Reaction with $NaHCO_3$

Alcohol $H_2$ is liberated No reaction No reaction

Phenol $H_2$ is liberated Soluble salt formed No reaction

Carboxylic acid $H_2$ is liberated Soluble salt formed $CO_2$ gas is liberated

Compound	Reaction with $Na$ metal	Reaction with $NaOH$	Reaction with $NaHCO_3$
Alcohol	$H_2$ is liberated	No reaction	No reaction
Phenol	$H_2$ is liberated	Soluble salt formed	No reaction
Carboxylic acid	$H_2$ is liberated	Soluble salt formed	$CO_2$ gas is liberated