A ball of mass m is thrown vertically upwards | vedclass

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(C) The time of flight $T$ for a projectile is given by $T = \frac{2u_y}{g}$,where $u_y$ is the vertical component of the initial velocity.Since both

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$1:1$

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(C) The time of flight $T$ for a projectile is given by $T = \frac{2u_y}{g}$,where $u_y$ is the vertical component of the initial velocity.Since both balls stay in the air for the same period of time,their vertical components of initial velocity $(u_y)$ must be equal.The maximum height attained by a projectile is given by $H = \frac{u_y^2}{2g}$.Since $u_y$ and $g$ are the same for both balls,the maximum height $H$ attained by both balls will be identical.Therefore,the ratio of the heights attained is $H_1 : H_2 = 1:1$.

$A$ ball of mass $m$ is thrown vertically upwards. Another ball of mass $2m$ is thrown at an angle $\theta$ with the vertical. Both of them stay in air for the same period of time. The heights attained by the two balls are in the ratio of

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