(B) The coefficient of linear expansion $\alpha$ determines how much a material changes its length with temperature change,given by $\Delta L = L_0 \a

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(B) The coefficient of linear expansion $\alpha$ determines how much a material changes its length with temperature change,given by $\Delta L = L_0 \alpha \Delta T$.Since the coefficient of linear expansion of metal $X$ is greater than that of metal $Y$ $(\alpha_X > \alpha_Y)$,metal $X$ will contract more than metal $Y$ when the temperature decreases (cooling).Because metal $X$ is on the left side and it contracts more than metal $Y$,the strip will bend towards the side that contracts more.Therefore,the bimetallic strip will bend towards the left.

Class 11 Physics 10-1.Thermometry, Thermal Expansion and Calorimetry Thermal Expansion for Solid

Medium

$A$ bimetallic strip consists of metals $X$ and $Y$. It is mounted rigidly at the base as shown. The metal $X$ has a higher coefficient of linear expansion compared to that for metal $Y$. When the bimetallic strip is placed in a cold bath:

AIIMS 2006 All AIIMS

A
It will bend towards the right
B
It will bend towards the left
C
It will not bend but shrink
D
It will neither bend nor shrink

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10-1.Thermometry, Thermal Expansion and Calorimetry

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Thermal Expansion for Solid

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$A$ pendulum clock loses $12\;s$ a day if the temperature is $40^{\circ}C$ and gains $4\;s$ a day if the temperature is $20^{\circ}C$. The temperature at which the clock will show correct time,and the coefficient of linear expansion $(\alpha)$ of the metal of the pendulum shaft are respectively:

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$A$ solid expands upon heating because

DifficultKVPY 2014

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The moment of inertia $I$ of a uniform rod about a perpendicular bisector increases to $I+\Delta I$, if the temperature is increased slightly by $\Delta T$. If the coefficient of linear expansion is $\alpha$, then $\frac{\Delta I}{I}$ is (Assume $\frac{\Delta T}{T} \ll 1$)

MediumTS EAMCET 2021

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$A$ hole is drilled in a copper sheet. The diameter of the hole is $4.24 \; cm$ at $27.0 \; ^{\circ}C$. What is the change in the diameter of the hole when the sheet is heated to $227 \; ^{\circ}C$? (Coefficient of linear expansion of copper $\alpha = 1.70 \times 10^{-5} \; K^{-1}$)

Medium

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The coefficient of linear expansion of a crystalline substance in one direction is $2 \times 10^{-4} /{ }^{\circ} C$ and in every direction perpendicular to it is $3 \times 10^{-4} /{ }^{\circ} C$. The coefficient of cubical expansion of the crystal is equal to ........... $\times 10^{-4} /{ }^{\circ} C$.

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$A$ bimetallic strip consists of metals $X$ and $Y$. It is mounted rigidly at the base as shown. The metal $X$ has a higher coefficient of linear expansion compared to that for metal $Y$. When the bimetallic strip is placed in a cold bath:

Similar Questions

$A$ pendulum clock loses $12\;s$ a day if the temperature is $40^{\circ}C$ and gains $4\;s$ a day if the temperature is $20^{\circ}C$. The temperature at which the clock will show correct time,and the coefficient of linear expansion $(\alpha)$ of the metal of the pendulum shaft are respectively:

$A$ solid expands upon heating because

The moment of inertia $I$ of a uniform rod about a perpendicular bisector increases to $I+\Delta I$, if the temperature is increased slightly by $\Delta T$. If the coefficient of linear expansion is $\alpha$, then $\frac{\Delta I}{I}$ is (Assume $\frac{\Delta T}{T} \ll 1$)

$A$ hole is drilled in a copper sheet. The diameter of the hole is $4.24 \; cm$ at $27.0 \; ^{\circ}C$. What is the change in the diameter of the hole when the sheet is heated to $227 \; ^{\circ}C$? (Coefficient of linear expansion of copper $\alpha = 1.70 \times 10^{-5} \; K^{-1}$)

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