The moment of inertia $I$ of a uniform rod about a perpendicular bisector increases to $I+\Delta I$, if the temperature is increased slightly by $\Delta T$. If the coefficient of linear expansion is $\alpha$, then $\frac{\Delta I}{I}$ is (Assume $\frac{\Delta T}{T} \ll 1$)

  • A
    $\alpha \Delta T$
  • B
    $2 \alpha \Delta T$
  • C
    $3 \alpha \Delta T$
  • D
    $4 \alpha \Delta T$

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