A black body at 200 K is found to emit maximu | vedclass

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(C) According to Wien's Displacement Law,the product of the wavelength corresponding to maximum energy emission $(\lambda_m)$ and the absolute tempera

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$2.8 \mu m$

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(C) According to Wien's Displacement Law,the product of the wavelength corresponding to maximum energy emission $(\lambda_m)$ and the absolute temperature $(T)$ is a constant.$\lambda_m T = b$ (constant)Given:$T_1 = 200 K$,$\lambda_{m1} = 14 \mu m$$T_2 = 1000 K$,$\lambda_{m2} = ?$Using the relation $\lambda_{m1} T_1 = \lambda_{m2} T_2$:$\lambda_{m2} = \frac{\lambda_{m1} T_1}{T_2}$$\lambda_{m2} = \frac{14 \mu m 	imes 200 K}{1000 K}$$\lambda_{m2} = \frac{2800}{1000} \mu m = 2.8 \mu m$Therefore,the correct option is $C$.

$A$ black body at $200 K$ is found to emit maximum energy at a wavelength of $14 \mu m$. When its temperature is raised to $1000 K$,the wavelength at which maximum energy is emitted is:

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